√2x+√3y=0,√3x-√8y=0 solve equations substitution method

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 1. Solve the following pair of linear equations by the substitution method.

(v) √2x+√3y=0,√3x-√8y=0

Solution:

√2x+√3y=0-----(1)

√3x-√8y=0-----(2)

Let we take equation (1) and make x form

√2x+√3y=0

√2x=-√3y

X=-√3y/√2-------(3)

Substitute x value in equation (2)

√3x-√8y=0

√3 (-√3y/√2)-√8y=0

=-3y/√2-√8y=0

=(-3y-√(16y)/) √2-=0

=(-3y-√(16y=) 0X√(2=0)

-3x-4y=0

Substitute y value in equation (3)

x=-3y/√2

x=3(0)/2=0/2=0

x=0 


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